Dividend in Quotient Module Is Noetherian If Both The Quotient And Divisor Are

Theorem

Let M by an R-module with a submodule N. Then if N and M/N are Noetherian, so is M.

Proof

Let M be an R-module with submodule N. Let L be an arbitrary submodule of M. We will prove that L is finitely generated, and thus M is Noetherian.

By the third isomorphism theorem we have that

LLNL+NN.

(L+N)/N is a submodule of M/N (the one corresponding with L+NM under the correspondence theorem) and thus finitely generated. As such, L/(LN) must be finitely generated, and hence suppose it is generated by {y1+LN,,yn+LN}. However LN is also finitely generated since it is a submodule of the Noetherian module N. As such, suppose LN is generated by {x1,,xk}.

We then have that L is generated by {y1,,yn,x1,,xk}.